Do you have a more efficient way to solve this? Or perhaps you want to try it in another language like or C++ ? Let me know in the comments!
def checkio(number): result = 1 # Convert number to string to iterate over digits for digit in str(number): if digit != '0': result *= int(digit) return result print(checkio(123405)) # Output: 120 Use code with caution. Copied to clipboard 2. Why Skip the Zeros? 123405
Want to see more algorithm breakdowns? Check out Algorithm blog post #3 on Medium for similar challenges! Do you have a more efficient way to solve this
The number is often used in coding challenges (like those on CheckiO) to teach basic algorithm logic, specifically how to calculate the product of digits while skipping zeros . def checkio(number): result = 1 # Convert number
The goal is simple: calculate the product of all digits, but . For 123405, the math looks like this:
The easiest way to talk to each digit is to turn the number into a string. This lets us loop through it like a list of characters.
Challenges like aren't just about math; they are about data integrity . Whether you are cleaning a database or writing a game engine, knowing how to filter out "noise" (like those zeros) while keeping the "signal" (the other digits) is what makes a great developer.